If `m_(1)` and `m_(2)` are masses of two reactants in any reaction, having their gram equivalent masses `E_(1)` and `E_(2)` respectively, which of the following equatios represents the law of equivence correctly?A. `m_(1)/m_(2)=E_(2)/E_(1)`B. `E_(1)E_(2)=m_(1)m_(2)`C. `m_(1)E_(2)=E_(1)m_(2)`D. `(m_(1)+m_(2))=(E_(1)+E_(2))`

If `m_(1)` and `m_(2)` are masses of two reactants in any reaction, ha

1.	If `m_(1)` and `m_(2)` are masses of two reactants in any reaction, having their gram equivalent masses `E_(1)` and `E_(2)` respectively, which of the following equatios represents the law of equivence correctly?A. `m_(1)/m_(2)=E_(2)/E_(1)`B. `E_(1)E_(2)=m_(1)m_(2)`C. `m_(1)E_(2)=E_(1)m_(2)`D. `(m_(1)+m_(2))=(E_(1)+E_(2))`
Answer» Correct Answer - C The correct formulae that expresses the law of equivalent correctly is `m_(1)E_(2)=E_(1)m_(2)`

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