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If m_(1), m_(2), m_(3) and m_(4) are respectively the magnitudes of the vectors a_(1)=2hati-hatj+hatk, a_(2)=3hati-4hatj-4hatk, a_(3)=hati+hatj-hatk and a_(4)=-hati+3hatj+hatk, then the correct order of m_(1),m_(2),m_(3) and m_(4) is |
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Answer» `m_(3)ltm_(1)ltm_(4)ltm_(2)` `m_(2)=|a_(2)|=sqrt(3^(2)+(-4)^(2)+(-4)^(2))=sqrt(41)` `m_(3)=|a_(3)|=sqrt(1^(2)+1^(2)+(-1)^(2))=sqrt(3)` and `m_(4)=|a_(4)|=sqrt((-1)^(2)+(3)^(2)+(1)^(2))=sqrt(11)` `therefore m_(3)ltm_(1)ltm_(4)ltm_(2)` |
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