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If `M(A,Z)`, `M_(p)and M_(n)` denote the masses of the nucleus `._(Z)X^(A)`, proton and neutron respectively in units of U (where`1U=931MeV//c^(2)`) and B.E. represents its B.E. in MeV, thenA. `M(A,Z)=ZM_(p)+(A-Z)M_(n)-BE`B. `M(A,Z)=ZM_(p)+(A-Z)M_(n)+BE//C^(2)`C. `M(A,Z)=ZM_(p)+(A-Z)M_(n)-BE//C^(2)`D. `M(A,Z)=ZM_(p)+(A-Z)M_(n)+BE` |
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Answer» Correct Answer - C Mass defect `Deltam=ZM_(p)+(A-Z)M_(n)-M(A,Z)` Binding energy `=DeltamC^(2)` `BE=[ZM_(p)+(A-Z)M_(n)-M(A,Z)].C^(2)` `M(A,Z)=ZM_(p)+(A-Z)M_(n)-(BE)/(C^(2))` |
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