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If M and N are any two events, then the probability that exactly one of them occurs isA. `P(M)+P(N)-2P(McapN)`B. `P(M)+P(N)-P(McapN)`C. `P(M)+P(N)+P(McapN)`D. `P(M)+P(N)+2P(McapN)` |
Answer» Correct Answer - B (b) If M and N are any two events. `therefore " "P(McupN)=P(M)+P(N)-P(McupN)` |
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