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If m is the mass of a body and E its K.E..then its linear momentum is(A) \(m\sqrt{E}\)(B) \(2\sqrt{m}E\)(C) \(\sqrt{m}E\)(D) \(\sqrt{2mE}\) |
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Answer» Correct option is: (D) \(\sqrt{2mE}\) \(E = \frac{1}{2} mv^2\) \(v = \sqrt \frac{2E}{m}\) \(P = mv\) \(P = m \sqrt \frac{2E}{m}\) \(P = \sqrt{2mE}\) Correct option is: (D) \(\sqrt{2mE}\) |
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