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If M is the midpoint of the side vec(BC) of a triangle ABC, prove that vec(AB)+vec(AC) = 2vec(AM) |
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Answer» Solution :Let M is the midpoint of BC of `triangleABC` Clearly `VEC(BM)` and `vec(CM)` are equal and OPPOSITE. Now `vec(AB)+vec(BM)` = `vec(AM)` and `vec(AC)+vec(CM)` = `vec(AM)` `implies vec(AB)+vec(AC)+vec(BM)+vec(CM)` = `2vec(AM)` `implies vec(AB)+vec(AC)` = `2vec(AM)` |
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