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If `M` is the molecular weight of `KMnO_(4)`, its equivalent weight will be when it is converted into `K_(2)MnO_(4)`A. `M`B. `M//3`C. `M//5`D. `M//7` |
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Answer» Correct Answer - A `2KMnO_(4)+2KOHto2K_(2)MnO_(4)+H_(2)O+[O]` or `Moverset(+7)(n)O_(4)^(-)+e^(-)to overset(+6)(Mn)O_(4)^(2-)` `:.` Eq. mass `=("Mol. Mass")/("Change in O.N.")=(M)/(1)=M` |
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