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If M1 suffers from channel length modulation but M2 doesn’t, what is the voltage gain?(a) gm1 * Rd || 1/gm2 * gm2 * Rd2(b) gm1 * Rd || 1/gm2 * gm2 * 2Rd2(c) gm1 * Rd || 12/gm2 * gm2 * Rd2(d) gm1 * Rd * gm2 * Rd2I had been asked this question by my college professor while I was bunking the class.My question comes from MOSFET Amplifier with CG Configuration in portion FET Amplifiers of Analog Circuits |
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Answer» RIGHT answer is (a) gm1 * Rd || 1/gm2 * gm2 * Rd2 Explanation: The voltage gain due to M1 is gm1 * Rd || 1/gm2 since we find that the drain of M1 is connected to the source of M2 and the impedance LOOKING into the source of a MOSFET is 1/gm2. Now, the voltage gain due to the 2ND CG STAGE is simply gm2*Rd2. Hence, the total voltage gain is a product of both the factors ie gm1 * Rd || 1/gm2 * gm2 * Rd2. |
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