1.

If mass of a planet is 8times the mass of the earth and it's radius is twice the radius of the earth, what will be the velocity for that planet

Answer»

launched from the Earth were EQUAL in MAGNITUDE to the potential energy, then in the absence of FRICTION RESISTANCE it could escape from the Earth.1/2mv^2=mgr1/2mv^2=mGM/r^2×r1/2mv^2=mGM/r1/2v^2=GM/rv=√(2GM/r) where M is mass of planet(for Earth 11.2 km/sec)



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