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If mass of a planet is 8times the mass of the earth and it's radius is twice the radius of the earth, what will be the velocity for that planet |
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Answer» launched from the Earth were EQUAL in MAGNITUDE to the potential energy, then in the absence of FRICTION RESISTANCE it could escape from the Earth.1/2mv^2=mgr1/2mv^2=mGM/r^2×r1/2mv^2=mGM/r1/2v^2=GM/rv=√(2GM/r) where M is mass of planet(for Earth 11.2 km/sec) |
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