InterviewSolution
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InterviewSolution
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If masses of all molecules of a gas are halved and the speed doubled. Then the ratio of initial and final pressure is : |
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Answer» Here, `M_(1)=M, C_(1)=C, V_(1)=V, P_(1) =?, M_(2)=M//2, C_(2)=2 C, V_(2)=V, P_(2)=?` As `P_(1)=1/3 (M_1)/(V_1) C_(1)^(2)` and `P_(2)= 1/3 (M_2)/(V_2) C_(2)^(2) :. (P_1)/(P_2) = (M_1)/(M_2) xx (V_2)/(V_1) xx (C_(1)^(2))/(C_(2)^(2)) = (M)/((M//2)) xx V/V xx ((C)/(2C))^(2)`. |
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