If mean is 10 and standard deviation is 2 for a Normal distribution, f

1.	If mean is 10 and standard deviation is 2 for a Normal distribution, find quartile deviation and mean deviation.
Answer» For the normal distribution Quartile deviation = \(\frac{2}{3}\) σ = \(\frac{2}{3}\) x 2 = 1.33. Mean deviation = \(\frac{4}{5}\) = \(\frac{4}{5}\) x 2 = 1.6.

If mean is 10 and standard deviation is 2 for a Normal distribution, find quartile deviation and mean deviation.

Answer»

For the normal distribution

Quartile deviation

= \(\frac{2}{3}\) σ = \(\frac{2}{3}\) x 2

= 1.33.

Mean deviation = \(\frac{4}{5}\)

= \(\frac{4}{5}\) x 2 = 1.6.