If mean radius of earth is R, its angular velocity is omega and the acceleration due to gravity at the surface of the earth is g. Then the cube of the radius of the orbit of geostationary satellite will be

If mean radius of earth is R, its angular velocity is omega and the ac

1.	If mean radius of earth is R, its angular velocity is omega and the acceleration due to gravity at the surface of the earth is g. Then the cube of the radius of the orbit of geostationary satellite will be
Answer» `(R^(2)g)/(omega^(2))` `(R^(2) omega^(2))/(g)` `(R^(2)g)/(omega)` `(RG)/(omega^(2))` Solution :Time PERIOD of SATELLITE, `T=(2pir^(3//2))/(sqrt(GM))or sqrt(GM)=(2pi)/(T).r^(3//2)` `(2pi)/(T)=omega` `:. omegar^(3//2)=sqrt(GM)or r^(3) =(GM)/(omega^(2))=(gR^(2))/(omega^(2))`