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If minutes is the unit of time. `10ms^(-2)` is the unit of acceleration and `100 kg` is the unit of mass, the new unit of work in joule isA. `10^(5)`B. `10^(6)`C. `6xx10^(6)`D. `36xx10^(6)` |
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Answer» Correct Answer - D `w alpha Ma^(2) T^(2) , (w_(2))/(w_(1)) = (M_(2) a_(2)^(2) T_(2)^(2))/(M_(1) a_(1)^(2) T_(1)^(2))` |
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