If molecular mass of solute base (M) & equivalent weight (E) are given the relation between Molarity (X) and Normality (Y).

If molecular mass of solute base (M) & equivalent weight (E) are given

1.	If molecular mass of solute base (M) & equivalent weight (E) are given the relation between Molarity (X) and Normality (Y).
Answer» `Y=(X XX M)/(E)` `X=(Y xx M)/(E)` `Y = (X xx E)/(M)` `X = Y xx E xx M` Solution :EQUIVALENT weight `=("Molecular MASS")/("Acidity")` `:.` Acidity `= M/E` NORMALITY of a base `=` MOLARITY `xx` Acidity `Y = (X xx M)/(E)`