If molecular weight of Na_(2)S_(2)O_(3) and I_(2) are M_(1) and M_(2) respectively then what will be equivalent weight of Na_(2)S_(2)O_(3) and I_(2) in the following redox reaction ? 2s_(2)O_(3)^(2-)+I_(2)rarrS_(4)O_(6)^(2-)+2I^(-)

If molecular weight of Na_(2)S_(2)O_(3) and I_(2) are M_(1) and M_(2)

1.	If molecular weight of Na_(2)S_(2)O_(3) and I_(2) are M_(1) and M_(2) respectively then what will be equivalent weight of Na_(2)S_(2)O_(3) and I_(2) in the following redox reaction ? 2s_(2)O_(3)^(2-)+I_(2)rarrS_(4)O_(6)^(2-)+2I^(-)
Answer» Solution :` 2Na_(2)S_(2)O_(3)=Na_(2)S_(4)O_(6)` TOTAL INCREASE is O.N of S for molecules of `Na_(2)S_(2)O_(3)=4xx2.5-2[2(+2)]=2` `therefore` Totalincrease in O.N of S PER molecule of `Na_(2)S_(2)O_(3)=1` `therefore` Eq mass =`M_(1)//1=M_(1)` now `I_(2)^(2)rarrr2I^(-1)` Total DECREASE is O.N per molecule of `I_(2)=0-2(-1)=2` `therefore` Eq mass of `I_(2)=M_(2)//2`