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If moment of inertia of a solid sphere of mass 5kg about its diameter is `50kg m^(2)` . Its moment of inertia about its tangent in kg `m^(2)` isA. 260B. 250C. 240D. 175 |
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Answer» Correct Answer - D `I_(0)=I_(C )+Mh^(2)` `=50+5xx25=50xx125=175 kg m^(2)`. |
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