1.

If momentum is increased by 20% then K.E increases by(A) 44%(B) 55%(C) 66%(D) 77%

Answer»

Answer is (A) 44%

K = p2/2m

K’ = [(1200/100)P]2/2m = 1.44 p2/2m = 1.44 K 

∆K = K’ – K = 0.44 K = 44 % K



Discussion

No Comment Found

Related InterviewSolutions