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If momentum is increased by 20% then kinetic energy increases by |
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Answer» Kinetic energy (E) is related with momentum (p) of a body of mass m as follows E=p^2/(2m) Let initial momentum be p .Then on 20% increase the changed momentum p'=120/100p=6/5p So E' =p'^2/(2m)=(36/25)p^2/(2m) =>E'/E=36/25 So percentage increase in KE =(E'-E)/E×100=(36-25)/25×100%=44% |
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