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If momentum of a body increase by 25% its kinetic energy will increase by |
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Answer» 25% `p_(2)/p_(1)=5/4impliesp^(2)5/4p_(1) therefore v_(2)=5/4v_(1)` `"kinetic energy"=1/2mv(2)` `Einftyv^(2) E_(2)=(25)/(16)E_(1)` `"Increase in"K.E.=(E_(2)-e_(1))/e_(1)XX100=((25)/(16)E_(1)-E_(1))/E_(1)xx100` `=((25-16)/16E_(1))/E_(1)xx100=9/(16)xx100=56.25%` |
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