1.

If momentum of a body increase by 25% its kinetic energy will increase by

Answer»

25%
5%
`125%`
56%

Solution :Let momentum of `p_(1)=100%"momentum of " p-(2)=125%`.
`p_(2)/p_(1)=5/4impliesp^(2)5/4p_(1) therefore v_(2)=5/4v_(1)`
`"kinetic energy"=1/2mv(2)`
`Einftyv^(2) E_(2)=(25)/(16)E_(1)`
`"Increase in"K.E.=(E_(2)-e_(1))/e_(1)XX100=((25)/(16)E_(1)-E_(1))/E_(1)xx100`
`=((25-16)/16E_(1))/E_(1)xx100=9/(16)xx100=56.25%`


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