If mu_s is the coefficient of static friction, the maximum speed V_("max") with which a vehicle can negotiate an unbanked curved track having radius R and inclined at an anglethetawith respect to horizontal plane is

If mu_s is the coefficient of static friction, the maximum speed V_("m

1.	If mu_s is the coefficient of static friction, the maximum speed V_("max") with which a vehicle can negotiate an unbanked curved track having radius R and inclined at an anglethetawith respect to horizontal plane is
Answer» `SQRT(Rgtantheta)` `sqrt(MU _s Rg)` `sqrt(Rg)` `sqrt((tan theta)/(Rg))` Solution : When the VEHICLE moves over an unbanked circular track, force of friction provides the necessary centripetal force. ` thereforef= ( mv^2) /(R )` As `f lemu_sN thereforev^2 le(mu_s RN )/(m)` ` orv^2lemu_sRg "" (:.N=mg)` ` thereforev_(MAX) = sqrt(mu_s Rg)`