If `mu_(v)=1.530 and mu_(R)=1.5145`, then disperisve power of a crown glass isA. 0.0164B. 0.00701C. 0.0132D. 0.032

If `mu_(v)=1.530 and mu_(R)=1.5145`, then disperisve power of a crown

1.	If `mu_(v)=1.530 and mu_(R)=1.5145`, then disperisve power of a crown glass isA. 0.0164B. 0.00701C. 0.0132D. 0.032
Answer» Correct Answer - A Here, `mu_(V)=1.5230 and mu_(R)=1.5145` Therefore, means refractive index. `mu=(1.523+1.5145)/(2)=1.5187` Now, disperisive power, `omega` is given by `omega=(mu_(V)-mu_(R))/(mu-1)=(1.5230-1.5145)/(1.51787-1)=0.0164`

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If `mu_(v)=1.530 and mu_(R)=1.5145`, then disperisve power of a crown glass isA. 0.0164B. 0.00701C. 0.0132D. 0.032

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