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If `n_(1)` denotes the maximum number of roots of `sin theta = k_(1)` in `[0,2pi]` and `n_(2)` denotes the maximum number of roots of `cos theta=k_(2)` in `[0,2pi]`, thenA. `n_(1)+n_(2)=5`B. `n_(1)+n_(2)=4`C. `n_(1)+n_(2)=6`D. `n_(1)+n_(2)=3` |
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Answer» Correct Answer - A `sin theta = k_(1)` has maximum roots if `k_(1) = 0` , so `theta = pi, pi, 2pi` `cos theta = k_(2)` has maximum roots if `k_(2) ne pm 1`, so there are two values of `theta` `therefore n_(1)=3` and `n_(2)=2` |
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