If (n + 2)! = 60[(n – 1)!], find n. – InterviewSolution

InterviewSolution

1.

If (n + 2)! = 60[(n – 1)!], find n.

Answer»

Given that (n + 2)! = 60(n – 1)!

(n + 2) (n + 1) n (n – 1)! = 60(n – 1)!

Cancelling (n – 1)! we get,

(n + 2)(n + 1)n = 60

(n + 2)(n + 1)n = 5 x 4 x 3

Both sides we consecutive product of integers

∴ n = 3

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