1.

If `(n+2)! = 60 xx (n-1)! `, find n.

Answer» We have
`(n+2)! = 60 xx (n-1)! `
` rArr (n+2)xx(n+1)xx nxx(n-1)! = 60 xx (n-1)! `
` rArr (n+2)(n+1)n=60 `
` rArr (n+2)(n+1)n= 5 xx 4 xx 3 `
[ writing 60 as product of 3 consecutive integers]
` rArr n=3. `
Hence,`n=3. `


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