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If `(""^(n+2)C_(6))/(""^(n-2)P_(2))=11`, then n satifes the equationA. `n^(2)+n-110=0`B. `n^(2)+5n-84=0`C. `n^(2)+3n-108=0`D. `n^(2)+2n=0` |
Answer» We have, `(""^(n+2)C_(6))/(""^(n-2)P_(2))=11` `implies((n+2)!)/((n-4)!6!)xx((n-4))/((n-2)!)=11` `implies(n+2)(n+1)(n)(n-1)=11xx6!` `implies(n+2)(n+1)(n)(n-1)=11xx10xx9xx8` `impliesn+2=11impliesn=9` This value of n satisfies the equation `n^(2)+3n-108=0`. |
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