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If (n + 3)! = 56 [(n + 1)!], find n. |
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Answer» Given : (n + 3)! = 56 [(n + 1)!] To Find : n ⇒ (n + 3) × (n + 2) × (n + 1)! = 56 [(n + 1)!] ⇒ (n + 3) × (n + 2) = 56 ⇒ (n + 3) × (n + 2) = 8 × 7 ⇒ n + 3 = 8 n = 5 Hence, n = 5 |
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