1.

If (n + 3)! = 56 [(n + 1)!], find n.

Answer»

Given : 

(n + 3)! = 56 [(n + 1)!] 

To Find :

⇒ (n + 3) × (n + 2) × (n + 1)! = 56 [(n + 1)!] 

⇒ (n + 3) × (n + 2) = 56 

⇒ (n + 3) × (n + 2) = 8 × 7 

⇒ n + 3 = 8 

n = 5 

Hence, 

n = 5



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