1.

If n[(A×B ) (A×C )]=8 and n(B∩C )=2 then n(A) is

Answer»

Consider,

n[(A x B)∩(A x C)]=8

n[A x (B∩C)] = 8

But n(A x B) = n(A) x n(B)

=> n(A) x n(B∩C) = 8

=> n(A) x 2=8

=> n(A) = 8/2

=> n(A) = 4



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