InterviewSolution
 Saved Bookmarks
    				| 1. | 
                                    If n is a natural number then 73n – 43n is always divisible by …(1) 11(2) 3 (3) 33 (4) both 11 and 3 | 
                            
| 
                                   
Answer»  (4) both 11 and 3 73n – 43n is of the form a2n – b2n which is divisible by both a – b and a + b. So 73n – 43n is divisible by both 7 – 4 = 3 and 7 + 4 = 11.  | 
                            |