Saved Bookmarks
| 1. |
If n is a product of k distinct primes what is the total number of factors of n ? |
|
Answer» Solution :n is a PRODUCT of k distinct primes. `:.` In order to be a factor, of n, we have choose at least one of k distinct primes. `:.` The NUMBER of ways. `= ""^kC_1+ ""^kC_2 + ……….. ""^kC_(k-1) =2^k-1-1` `:. "The number of factors of n is "2^k-2`. (EXCLUDING 1 as 1 is not PRIME . It is also not include n.) |
|