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If NaCl is doped with 10-3 mol % of SrCl2 , what is the concentration of cation vacancies? |
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Answer» Every Sr2+ ion causes one cation vacancy (because two Na+ ions are replaced by one Sr2+ and it occupies the site of one Na+ ion and the other site remains vacant.) Therefore, introduction of 10-3 moles of SrCl2 per 100 moles of NaCl would introduce 10-3 moles cation vacancies in 100 moles of NaCl. No. of vacancies per mole of NaCl = \(\frac{10^{-3}}{100}\times6.02\times10^{23}\) = 6.02 × 1018 |
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