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If nPr = 1680 and nCr = 70, find n and r. |
Answer» Given that nPr = 1680, nCr = 70 We know that nCr = \(\frac{nP_r}{r!}\) 70 = \(\frac{1680}{r!}\) r! = \(\frac{1680}{70}\) = 24 r! = 4 x 3 x 2 x 1 = 4! ∴ r = 4 |
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