1.

If ω≠1 is a cube root of unity and ∣∣∣∣∣x+ω2ω1ωω21+x1x+ωω2∣∣∣∣∣=0, then value of x is

Answer»

If ω≠1 is a cube root of unity and ∣∣
∣
∣
∣
x+ω2ω1ωω21+x1x+ωω2∣∣
∣
∣
∣
=0
, then value of x is





Discussion

No Comment Found