1.

If ω≠1 is a cube root of unity and ∣∣∣∣∣x+ω2ω1ωω21+x1x+ωω2∣∣∣∣∣=0, then value of x is

Answer»

If ω1 is a cube root of unity and

x+ω2ω1ωω21+x1x+ωω2

=0
, then value of x is





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