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If O and O' denote respectively the circumcente and orthocentre of Delta ABC, then O' A + O' B + O' C is equal orthocentre of delta ABC, then O'A + O' B + O' C is equal to |
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Answer» O' O Now, we have `OA+OB + OC = 3OG` `implies OA+ OB + OC = 2OG + OG` `implies OA + OB + OC = GO + OG""[:'2OG=GO ]` `impliesOA +OB+OC=OO'` |
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