1.

If O and O' denote respectively the circumcente and orthocentre of Delta ABC, then O' A + O' B + O' C is equal orthocentre of delta ABC, then O'A + O' B + O' C is equal to

Answer»

O' O
O O '
20'0
O

Solution :Let G be the CENTROID of Delta ABC. Then, O', G, O are collinear and G divides O' O in the ratio 2 : 1` I, e, (O' G)/ (OG)= 2/1 `
Now, we have
`OA+OB + OC = 3OG`
`implies OA+ OB + OC = 2OG + OG`
`implies OA + OB + OC = GO + OG""[:'2OG=GO ]`
`impliesOA +OB+OC=OO'`


Discussion

No Comment Found

Related InterviewSolutions