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if O is the point inside the triangle ABC such that /_OBC = A/2, /_OCA = B/2, /_AOB = C/2, then (sin(A - C/2)sin(B - A/2)sin(C - B/2))/(sin""(A)/2 sin""(B)/2 sin""(C)/2) equal : |
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Answer» `COS""A/2 cos""B/2 cos""C/2` |
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