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If `omega = z//[z-(1//3)i] and |omega| = 1`, then find the locus of z. |
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Answer» Correct Answer - Perpendicular bisector of the line joininig 0+ 0i and `0 + (1//3)i` `omega = (z)/(z-(1)/(2)i)` or ` |omega| = |(z)/(z-(1)/(3)i)|` or ` |z| = |omega||z-(1)/(3)i|` or ` |z| = |z-(1)/(3)i|" "(because |omega|=1)` Hence, locous of z is perpendicular bisector of the line joining `0 + 0i` and `0+(1//3)i`. Hence z lies on a straight line . |
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