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If one end of the diameter is (1, 1) and the other end lies on the line`x+y=3`, then find the locus of the center of the circle.A. `x+y=1`B. `2(x-y)=5`C. `2x+2y=5`D. none of these |
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Answer» Correct Answer - C Let the coordinates of the other end of the diameter be (t, 3-t). Then, the equation of the circle is `(x-1)(x-t)+(y-1)(y-3+t)=0` `rArr x^(2)+y^(2)-(1+t)x-(4-t)y+3=0` Let (h, k) be the coordinates of the centre. `:. H=(1+t)/(2), k=(4-t)/(2)` `rArr 2h-1=-2k+4 " " `[On eliminating t] `rArr 2(h+k)=5` Hence, the locus of (h, k) is `2(x+y)=5`. |
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