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If one invests Rs. 10,000 in a bank at a rate of interest 8% per annum, how long does it take to double the money by compound interest? [(1.08)5 = 1.47] |
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Answer» Amount invested = Rs. 10000 Interest rate = \(\frac8{100}=0.08\) amount after 1st year = 10000(1 + 0.08) = 10000(1.08) Value of the amount after n years = 10000(1.08) × (1.08)n-1 = 10000(1.08)n = 20000 ∴ (1.08)n = 2 ∴ (1.08)5= 1.47 …..[Given] ∴ n = 10 years, (approximately) |
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