1.

If one invests Rs. 10,000 in a bank at a rate of interest 8% per annum, how long does it take to double the money by compound interest? [(1.08)5 = 1.47]

Answer»

Amount invested = Rs. 10000

Interest rate = \(\frac8{100}=0.08\) 

amount after 1st year = 10000(1 + 0.08)

= 10000(1.08)

Value of the amount after n years

= 10000(1.08) × (1.08)n-1

= 10000(1.08)n

= 20000

∴ (1.08)n = 2

∴ (1.08)5= 1.47 …..[Given]

∴ n = 10 years, (approximately)



Discussion

No Comment Found