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If one mole of a monatomic gas `(gamma=5/3)` is mixed with one mole of a diatomic gas `(gamma=7/5),` the value of gamma for mixture isA. `1.40`B. `1.50`C. `1.53`D. `3.07` |
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Answer» Correct Answer - B `gamma_(1)=5//3` means gas is monatomic or `C_(v_(1))=(3)/(2)R` `gamma_(2)=7//5` means gas is diatomic or `C_(v_(2))=5//2R` `C_(v)` (of the mixture) `=(n_(1)C_(v_(1))+n_(2)C_(v_(2)))/(n_(1)+n_(2))=((1)((3)/(2)R)+(1)((5)/(2))R)/(1+1)=2R` `C_(p)` (of the mixture) `=C_(v)+R=3R` `gamma_("mixture")=(C_(p))/(C_(v))=(3R)/(2R)=1.5` |
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