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If one organic compound has C & H respectively 92.3% and 7.7% then its empirical formula is..... |
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Answer» Solution :`C= 92.3% ,H= 7.7%` `C:H= (92.3)/(12)= (7.7)/(1) = 7.7:7.7=1:1` Empirical formula `=CH` |
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