1.

If one organic compound has C & H respectively 92.3% and 7.7% then its empirical formula is.....

Answer»

CH
`CH_(3)`
`CH_(2)`
`CH_(4)`

Solution :`C= 92.3% ,H= 7.7%`
`C:H= (92.3)/(12)= (7.7)/(1) = 7.7:7.7=1:1`
Empirical formula `=CH`


Discussion

No Comment Found