1.

If one root of the equation x2 + px + 12 = 0 is 4, while the equation x2 + px + q = 0 has equal roots, the value of q is

Answer»

One root of the equation x2+px+12=0 is 4

⇒16+4p+12=0

∴p=−7

as x2+px+q=0 has equal roots.

b2 =4ac  ⇒p2=4q

\(\therefore q=\frac{49}{4}\)



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