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If one root of the equation x2 + px + 12 = 0 is 4, while the equation x2 + px + q = 0 has equal roots, the value of q is |
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Answer» One root of the equation x2+px+12=0 is 4 ⇒16+4p+12=0 ∴p=−7 as x2+px+q=0 has equal roots. b2 =4ac ⇒p2=4q \(\therefore q=\frac{49}{4}\) |
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