If one root of x 13RT n Tmte AABC-A0RPun artAARP) _ 4澗BC-15ǐ.4.naPR

1.	If one root of x 13RT n Tmte AABC-A0RPun artAARP) _ 4澗BC-15ǐ.4.naPR:m秫찌4ar(AQRP) 4Ir AABC AORP(R)and BC - 15 em, then find PR,a AABC) 9
Answer» Given : Area of ∆ ABCArea of ∆QRP = 9/4 AB = 18 cm , BC = 15 cm So PR = ? We know when two triangles are similar then " The areas of two similar triangles are proportional to the squares of their corresponding sides. Area of ∆ ABCArea of ∆ QRP = AB2/QR2 = BC2/PR2 = AC2/QP2So , we take Area of ∆ ABC/Area of ∆ QRP = BC2/PR2 Now substitute all given values and get 9/4 = 15²/PR² Taking square root on both hand side , we get PR = 10 cm

If one root of x 13RT n Tmte AABC-A0RPun artAARP) _ 4澗BC-15ǐ.4.naPR:m秫찌4ar(AQRP) 4Ir AABC AORP(R)and BC - 15 em, then find PR,a AABC) 9

Answer»

Given :

Area of ∆ ABCArea of ∆QRP = 9/4

AB = 18 cm , BC = 15 cm So PR = ?

We know when two triangles are similar then " The areas of two similar triangles are proportional to the squares of their corresponding sides.

Area of ∆ ABCArea of ∆ QRP = AB2/QR2 = BC2/PR2 = AC2/QP2So , we take Area of ∆ ABC/Area of ∆ QRP = BC2/PR2

Now substitute all given values and get

9/4 = 15²/PR²

Taking square root on both hand side , we get

PR = 10 cm