1.

If P = 106 kT, then the number of molecules per unit volume of the gas is [the letters have usual meanings.]

Answer»

<P>`100 K`
`300 K`
`502 K`
`546 K`

SOLUTION :`PV = mu RT = n/N kNT = nkT`
or `n/V = P/(kT) = (10^(6)kt)/(kT) = 10^(6)`.


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