If p=2-a, then prove that a^3+6ap+p^3-8=0

1.	If p=2-a, then prove that a^3+6ap+p^3-8=0
Answer» a^3 + 6ap +p^3 - 8= a^3 + 6a ( 2 - a) + ( 2 - a)^3 - 8= a^3 + 12a - 6a^2 + (2)^3 - a^3 - 3 (2)^2 (a) + 3 (2)(a)^2 - 8= a^3 + 12a - 6a^2 + 8 - a^3 - 12a + 6a^2 - 8 = 0.Hence proved.

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