1.

If p = -2, q = 1 and r = 3, find the value of 3p2q2r.

Answer»

Given p = -2; 

q = 1; 

r = 3

∴ 3p2q2r = 3 x (-2)2 x (1)2 x (3)

= 3 x (-2 x 1)2 x (3) 

[Since am x bm = (a x b)m]

= 3 x (-2)2 x (3)

= 3 x (-1)2 x 2x 3

= 31+1 x 1 x 4 

[Since am x an = am+n]

= 32 x 4 = 9 x 4

∴ 3p2q2r = 36



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