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If `P (32, 6) = kC(32, 6)`, then what is the value of k?A. 6B. 32C. 120D. 720 |
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Answer» Correct Answer - D Since `.^(32)P_(6) = k .^(32)C_(6)` `rArr (32!)/((32 -6)!) = k (32!)/(6!(32 -6)!)` `rArr k = 6! = 720` |
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