If P=[5−3111336] and det(−3P2013+P2014)=ααβ2(1+γ+γ2) where α – InterviewSolution

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1.	If P=[5−3111336] and det(−3P2013+P2014)=ααβ2(1+γ+γ2) where α,β,γ are natural numbers, then
Answer» If $P = [\begin{matrix} 5 & - 3 111 & 336 \end{matrix}]$ and $det (- 3 P^{2013} + P^{2014}) = α^{α} β^{2} (1 + γ + γ^{2})$ where $α, β, γ$ are natural numbers, then

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