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If P(A)=0.4,P(B)=0.8 and P(B/A)=0.6, then `P(AcupB)` is equal toA. 0.24B. 0.3C. 0.48D. 0.96 |
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Answer» Here, P(A)=0.4,P(B)=0.8andP(A/B)=0.6 `because P(B//A)=(P(BcapA))/(P(A))` `rArr P(BcapA)=P(B//A)cdotP(A)` `=0.6xx0.4=0.24` `thereforeP(AcupB)=P(A)+P(B)-P(AcapB)` `=0.4+0.8-0.24` `=1.2-0.24=0.96` |
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