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If P(A)=0.8, P(B)=0.5 and P(B/A)=0.4 . Find (A∩B). |
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Answer» P(\(\frac{B}{A}\)) = \(\frac{P(B ∩ A)}{P(A)}\) ⇒ 0.4 x 0.8 = P(B∩A) ⇒ P(B∩A) = 0.32 |
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