1.

If P[A]=1/8, P[B]=1/6 and P[A∪B]=1/10, find P[A ∩ B].

Answer»

P(A∪B) = P(A) + P(B) – P(A∩B)

1/10= 1/8+ 1/16 – P(A∩B)

P(A∩B)= 1/8 + 1/16 – 1/10 

= 0.0875



Discussion

No Comment Found