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If P[A]=1/8, P[B]=1/6 and P[A∪B]=1/10, find P[A ∩ B]. |
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Answer» P(A∪B) = P(A) + P(B) – P(A∩B) 1/10= 1/8+ 1/16 – P(A∩B) P(A∩B)= 1/8 + 1/16 – 1/10 = 0.0875 |
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