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If ‘p’ and ‘q’ are distance of object and image from principal focus of a concave mirror then what is the relation between ‘p’, ‘q’ and ‘f’? 1. pq = √f2. pq = f 3. pq = f2 4. pq = 1/f |
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Answer» 3. pq = f2 \(\frac{1}{\text{V}}+\frac{1}{\text{U}} =\frac{1}{\text{f}}\) ⇒ \(\frac{1}{F+b}+\frac{1}{f+q}=\frac{1}{f}\) ⇒ f2 = qp |
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